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A number doubled then increases by three is more than 6 but less than 20. Write and solve an inequality that represents this scenario.

User MichaelP
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Answer:

Explanation

Let the number be y

y doubled = y×2=2y

2y increases by 3 = 2y+3=

2y +3 is more than 6 but less than 20

2y+3 > 6

2y+3< 20

Solve for y

2y>6-3

y>3/2

2y+3<20

2y<20-3

2y<17

y<17/2

User Prannoy Mittal
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