Answer:
Explanation
Let the number be y
y doubled = y×2=2y
2y increases by 3 = 2y+3=
2y +3 is more than 6 but less than 20
2y+3 > 6
2y+3< 20
Solve for y
2y>6-3
y>3/2
2y+3<20
2y<20-3
2y<17
y<17/2
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