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a box weighing 155 N is pushed horizontally down the hall at constant velocity. the applied force is 83 n what is the coefficient of friction between the box and the floor

User Bob Kusik
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1 Answer

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Answer:

μ = 0.535

Step-by-step explanation:

On a level floor, normal force = weight.

N = W

Friction force = normal force × coefficient of friction.

F = Nμ

Substitute:

F = Wμ

83 = 155μ

μ = 0.535

Round as needed.

User Ikram Khan Niazi
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7.7k points