Question

At which values of x does the graph of the function F(x) have a vertical asymptote? Check all that apply f(x)=1/(x+1)(x+2)

Answer 1

Answer: -1 and -2

Explanation:

Answer 2

x=-1 and x=-2

Explanation:

Given

`f(x)=(1)/((x+1)(x+2))`

This function is undefined when the denominator becomes 0. Find values of x for which the denominator is 0:

`(x+1)(x+2)=0\\ \\x+1=0\ \text{or}\ x+2=0\\ \\x=-1\ \text{or}\ x=-2`

Thus, the lines with equations
`x=-1` and
`x=-2` represent vertical asymptotes (see attached graph)