Question

Explain the answer because im stuck

Answer 1

The Proof is given below.

Explanation:

Given:

`\overline{HF}` bisect ∠ EHG.i.e

∴ ∠EHF ≅ ∠ GHF

`\overline{EH} \cong \overline{GH}`

To Prove:

`\overline{EF} \cong \overline{GF}`

Proof:

In Δ EHF and Δ GHF

EH ≅ GH ………............{Given}

∠ EHF ≅ ∠ GHF …………..{EF bisect ∠ EHG as given above}

HF ≅ HF ………............{Reflexive Property}

Δ EHF ≅ Δ GHF …................{ By Side-Angle-Side test}

∴ EF ≅ GF........{corresponding parts of congruent triangles (c.p.c.t).}

`\overline{EF} \cong \overline{GF}` ....... PROVED