Question

Determine the h+ of 0.005 KOH​

Answer 1

[H⁺] = 2.0 × 10⁻¹² M

Step-by-step explanation:

Given data:

Concentration of KOH = 0.005M

H⁺ = ?

Solution:

pOH = -log[ OH⁻]

pOH = -log[0.005]

pOH = 2.3

pH + pOH = 14

14 - pOH = pH

pH = 14 - 2.3

pH = 11.7

pH = -log[H⁺]

11.7 = -log[H⁺]

[H⁺] = Antilog (-11.7)

[H⁺] = 2.0 × 10⁻¹² M