Answer:
Explanation:
Perimeter of a rectangle is expressed as (2 length + 2 width) = 2(L + W)
A) The length of rectangle A is y + 1
The width of rectangle A is x
Perimeter of rectangle A = 2(y + 1 + x) = 2y + 2 + 2x
= 2x + 2y + 2
The length of rectangle B is 2x - 2y
The width of rectangle B is x + 1
Perimeter of rectangle B = 2(2x - 2y+ x + 1) = 4x - 4y + 2x + 2) = 4x + 2x - 4y + 2
= 6x - 4y + 2
The length of rectangle C is 3x + 3y
The width of rectangle C is 2x - 3
Perimeter of rectangle C = 2(3x + 3y + 2x - 3) = 6x + 6y + 4x - 6) =
(6x + 6y + 4x - 6)
= 10x + 6y - 6
B) The combined perimeters will be the sum if perimeter of rectangle A, perimeter of rectangle B and perimeter of rectangle C. It becomes
2x + 2y + 2 + 6x - 4y + 2 + 10x + 6y - 6
Collecting like terms
2x + 6x + 10x + 2y + 6y - 4y + 2 + 2 - 6
The combined perimeter = 18x + 4y - 2