Question

What is angle a? ive already gotten the other side

Answer 1

`m\angle A=\tan^(-1)((m)/(n))`

`AB=√(m^2+n^2)`

Explanation:

Given:

In Δ ABC

m∠C= 90°

`BC=m`

`AC=n`

For the triangle ABC we can apply trigonometric ratio to find m∠A.

We have:

`\tan\angle A=(BC)/(AC)`

Substituting values of side BC and AC

`\tan \angle A=(m)/(n)`

Taking inverse tan to get m∠A.

∴
`m\angle A=\tan^(-1)((m)/(n))`

AB can be found out using Pythagorean theorem:

AB being the hypotenuse can be written as

`AB^2=BC^2+AC^2`

Substituting values of side BC and AC

`AB^2=m^2+n^2`

Taking square roots both sides:

`√(AB^2)=√(m^2+n^2)`

∴
`AB=√(m^2+n^2)`