Question

How many milliliters of a 0.223 M KNO3 solution contain 0.250 moles of KNO3?

Answer 1

1121.08 millilitres of 0.223 M
`KNO_(3)` solution contains 0.250 moles of
`KNO_(3)`.

Step-by-step explanation:

The formula for molarity of a solution:

`Molarity=(n)/(V)\\ where,n=number\: of\:moles\\V=volume\:of\:solution\:in\:L`

Molarity = 0.223 M

n = 0.250 moles

`V=(n)/(Molarity)=(0.250)/(0.223)=1.12108L=1121.08mL`

Therefore, 1121.08 millilitres of 0.223 M
`KNO_(3)` solution contains 0.250 moles of
`KNO_(3)`.