The amount invested in the mutual fund that earned 5% is $ 1000
The amount invested in the mutual fund that earned 3% is $ 1800
Solution:
Given that , An investor invested a total of $2,800 in two mutual funds
Let the amount invested in 1st mutual fund be $n
Then the amount invested in the other mutual fund will be $(2800 - n)
One fund earned 5% profit while the other earned 3% profit
Then, profit earned by 1st fund ⇒ 5% of n
And profit earned by 2nd fund ⇒ 3% of 2800 – n
Investor's total profit was $104
Now, we know that,
total profit = profit earned on 1st fund + profit earned on 2nd fund
104 = 5% of n + 3% of ((2800 - n)
![(5)/(100) n+(3)/(100)(2800-n)=104](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8bwh9bqhwf2wp6pm7tep4f0al5lohvhpbi.png)
![\begin{array}{l}{(5 n+3(2800-n))/(100)=104} \\\\ {5 n+3 * 2800-3 n=10400} \\\\ {5 n-3 n=10400-8400} \\\\ {2 n=2000} \\\\ {n=1000}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/flppeb0zu825hg2v5qo3t54sxre8tcosn6.png)
So, he invested $ 1000 in 1st fund at 5 % profit
And 2800 – n = 2800 - 1000 = $ 1800 in 2nd fund at 3 % profit