Question

mariko says that the graph that passes through (-3,-3), (-3,0) and (-3,3) represents linear function.is she correct.explain your reasoning

Answer 1

The graph that passes through (-3,-3), (-3,0) and (-3,3) does not represents linear function

Explanation:

Mariko says that the graph that passes through (-3,-3), (-3,0) and (-3,3)

Now, the line joining (-3,-3) and (-3,0) has slope =
`(-3 - 0)/(- 3 -(- 3)) =` = ∞

Again, the line joining (-3, 0) and (-3,3) has slope =
`(0 - 3)/(- 3 -(- 3)) =` = ∞

Therefore, both the lines are parallel to y-axis and has a common point (-3,0). {Since, tan Ф = ∞, ⇒ Ф = 90°}

So, the graph that passes through (-3,-3), (-3,0) and (-3,3) does not represents linear function as the graph represents a vertical line parallel to y-axis. (Answer)