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What is the monomial if a square of a monomial is:1 9/16 a12b6

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Answer:


1(1)/(4)a^6b^3

Explanation:

A square of a monomial is
1(9)/(16)a^(12)b^6 that is
(25)/(16)a^(12)b^(6)

Use properties of exponents:


(a^m)^n=a^(mn)\\ \\(a^m)/(b^m)=\left((a)/(b)\right)^m\\ \\a^mb^m=(ab)^m

Note that


(25)/(16)=(5^2)/(4^2)=\left((5)/(4)\right)^2\\ \\a^(12)=a^(6\cdot 2)=(a^6)^2\\ \\b^6=b^(3\cdot 2)=(b^3)^2

Then


(25)/(16)a^(12)b^(6)=\left((5)/(4)\right)^2\cdot (a^6)^2\cdot (b^(3))^2=\left((5)/(4)a^6b^3\right)^2

So, the monomial is


(5)/(4)a^6b^3=1(1)/(4)a^6b^3

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