Question

Given sin 60 degrees = square root of 3 divided by 2 , find cos 60 degrees.

Answer 1

cos60° =
`(1)/(2)`

Explanation:

Using the trigonometric identity

sin²x + cos²x = 1 ⇒ cos x =
`√(1-sin^2x)`

Given

sin60° =
`(√(3) )/(2)`, then

cos60° =
`\sqrt{1-((√(3) )/(2))^2 }` =
`\sqrt{1-(3)/(4) }` =
`\sqrt{(1)/(4) }` =
`(1)/(2)`