Question

The Young�s modulus for steel is 20.7*1010 N/m2. How much will a 2.5 mm diameter wire 12 cm long, be strained when it supports a load of 450 N?

Answer 1

ΔL = 53.14*10⁻⁶ m

Step-by-step explanation:

Given

E = 20.7*10¹⁰ N/m²

D = 2.5 mm = 2.5*10⁻³ m

L = 12 cm = 0.12 m

P = 450 N

ΔL = ?

We can use the formula

ΔL = P*L / (A*E)

where A = π*D² / 4 = π*(2.5*10⁻³ m)² / 4

⇒ A = 4.908*10⁻⁶ m²

then

ΔL = (450 N)*(0.12 m) / (4.908*10⁻⁶ m²*20.7*10¹⁰ N/m²) = 53.14*10⁻⁶ m