Answer:
a=55
b=5
T=17
Explanation:
The general form of the equation is:
![N(t)=ab^{(t)/(T)}](https://img.qammunity.org/2020/formulas/mathematics/college/h37t9x2b0lhktyixybiceo60dn6wuu1n0c.png)
For t = 0:
![N(0)=ab^{(0)/(T)}\\N(0) = a = 55\\a=55](https://img.qammunity.org/2020/formulas/mathematics/college/se2v93odl3fz7290y8cs3b26mtdhnyn2us.png)
Since there has been a fivefold increase after 17 years, at t = 17, N(17) = 55*5
![N(17)=55b^{(17)/(T)}\\55*5 = 55b^{(17)/(T)}\\b^{(17)/(T)} = 5](https://img.qammunity.org/2020/formulas/mathematics/college/5ug8p7zqb70mfdb04ns5tf9wrdu9uoofut.png)
If at every 17*n years there in an increase of 5^n, one can deduct that the values for T and b are respectively 17 and 5:
![b^{(t)/(T)}= 5^{(17n)/(17)}](https://img.qammunity.org/2020/formulas/mathematics/college/q4cj55b2x6q2g4b234hplkxhcmk34ipw7m.png)
Therefore, the function that represents N(t) is:
![N(t)=55*5^{(t)/(17)}](https://img.qammunity.org/2020/formulas/mathematics/college/lp0zyi1zsxjwvtt1pt7di0i8x95sf3wyeq.png)