3x +10 < 3 or 2x -5 > 5

Question

asked Mar 27, 2020 24.2k views

1 Answer

Hardik Thakkar · Answer 1 · 2020-04-03T15:04:43+0000

For this case we must find the solution set of the given inequalities:

Inequality 1:

3x + 10 <3

Subtracting 10 from both sides of the inequality:

3x <3-10

Different signs are subtracted and the major sign is placed.

3x <-7

We divide between 3 on both sides of the inequality:

$x <- \frac {7} {3}$

The solution is given by all values of x less than
$- \frac {7} {3}$

Inequality 2:

2x-5> 5

Adding 5 to both sides of the inequality:

$2x> 5 + 5\\2x> 10$

Dividing by 2 to both sides of the inequality:

$x> \frac {10} {2}\\x> 5$

The solution is given by all values of x greater than 5.

Thus, the solution set is given by:

(-∞,
$- \frac {7} {3}$ ) U (5,∞)

ANswer:

(-∞,
$- \frac {7} {3}$ ) U (5,∞)