Answer:
Let's x be the probability for 1, 3, 5 and 6.
The probability for 2 and 4 is going to be 3x.
The sum of the probabilities of all possible outcomes is always 1.
P(1) + P(2) + P(3) + P(4) + P(5) + P(6) = 1
x + 3x + x + 3x + x + x = 1
10x = 1
x = 1/10
The probability of obtaining 1, 3, 5 or 6 is 1/10
The probability for 2 and 4 is 3/10