Question

9. A baseball pitcher hurls a 400 g baseball toward a batter with a speed of 30 m/s. The batter hits the pitch directly back toward the pitcher and it travels at 38 m/s. If the collision with the bat required 80 ms (milliseconds), find the force the bat applies to the ball. (Watch signs.)

Answer 1

The force the bat applies to the ball is 340 N

Step-by-step explanation:

given information:

mass of the ball, m = 400 g = 0.4 kg

initial velocity,
`v_(i)` = 30 m/s

final velocity,
`v_(f)` = 38 m/s

time, t = 80 ms = 0.08 s

the correlation between the change in momentum and the force is shown by the following equation

ΔP = FΔt

F = ΔP/Δt

where,

Δp = mΔv

= m(
`v_(f) - v_(i)`)

= m(
`v_(f) + v_(i)`)

`v_(i)` = - because in opposite direction, thus

F = ΔP/Δt

= m(
`v_(f) + v_(i)`)/Δt

= (0.4)(38+30)/0.08

= 340 N