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Centrifuge is usually used to separate the various components in a whole blood. One intends to separate the red blood cells from the plasma in a sample of whole blood in a centrifuge of radius 0.350 m. If the mass of the red blood cell is 3.00 X 10-16 kg and the necessary force to separate the red blood cell from the plasma is 4.12 X 10-11 N, what is the angular speed the centrifuge should be operated?

1 Answer

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Answer:

1084.94 rad/s

Step-by-step explanation:

The force exerted in any circular motion is given by


F = (mv^2)/(r)

Where m is the mass of the mass of the body

v is the speed of the body and

r is the radius of the circular path

F is the centrifugal force

Substituting the given values in above equation, we get


4.12 * 10^(-11) = (3 * 10^(-16)^ v^2)/(0.350)\\v = \sqrt{(4.12 * 10^(-11) * 0.350)/(3 * 10^(-16)) } \\v = 379.73 m/s

For calculating angular velocity, "v" is to be divided by "r"

Angular velocity is equal to


(379.73)/(0.35) \\1084.94 rad/s

User Waqas Raja
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