Answer:
![\Delta V\%=49.25\%](https://img.qammunity.org/2020/formulas/physics/high-school/gwd1578u9fcj138jx8oligw7rhjtmdfl9k.png)
Step-by-step explanation:
Assuming the pressure inside the packet at the time of packaging,
![P_a=1\ atm](https://img.qammunity.org/2020/formulas/physics/high-school/tmwop9tyhvhcqo1b9vd0ncgpk69nt8og0k.png)
Given that there is no temperature difference between the air inside the pack and the cabin.
Using mathematical expression of Boyle's law:
![P_1.V_1=P_2.V_2](https://img.qammunity.org/2020/formulas/physics/high-school/91gluvudkkaz3zobshvxvf8r1ctz3fm2yi.png)
where subscripts 1 & 2 denote the initial and final conditions respectively.
![1* V_1=0.67* V_2](https://img.qammunity.org/2020/formulas/physics/high-school/rvwlnqlp0df9xzziame6e1g7vca7ai536z.png)
![V_2=(V_1)/(0.67)](https://img.qammunity.org/2020/formulas/physics/high-school/n26eopl8zxe8faq8jn5xtx37qa7o8acyyf.png)
Now change in volume:
![\Delta V=V_2-V_1](https://img.qammunity.org/2020/formulas/physics/high-school/hlrr1f0vylziacu5ae0n8yialjyc9rmfsa.png)
![\Delta V=(V_1)/(0.67)-V_1](https://img.qammunity.org/2020/formulas/physics/high-school/o8xhbrtzuf9uz8o2pguk6iaah5zfk3601g.png)
![\Delta V=0.4925\ V_1](https://img.qammunity.org/2020/formulas/physics/high-school/gcr7tjjy2gnt79yl6iu9jh84xzuslz84ff.png)
Now the % increase in volume:
![\Delta V\%=(\Delta V)/(V_1) * 100](https://img.qammunity.org/2020/formulas/physics/high-school/sj5lvoezodg4kg3sdnyvvdkghf4rjvcqaa.png)
![\Delta V\%=49.25\%](https://img.qammunity.org/2020/formulas/physics/high-school/gwd1578u9fcj138jx8oligw7rhjtmdfl9k.png)