Answer:
The average distance is 999.936 light years.
Solution:
As per the question:
Ours is the Milky Way Galaxy with the diameter:
D = 1,00,000 ly
Radius, R =
![(D)/(2) = (1,00,000)/(2) = 50,000\ ly](https://img.qammunity.org/2020/formulas/physics/high-school/5rxlanct8pnlca3r8z7zpbyu96o73fnmv6.png)
Now,
A =
![\pi R^(2) = 50,000^(2)\pi = 7.8539* 10^(9)\ ly^(2)](https://img.qammunity.org/2020/formulas/physics/high-school/ghycxvn4ns0afv22cqhnn7jwtoyn31hddz.png)
The area to each civilization, A' is:
A' =
![(A)/(10000) = (7.8539* 10^(9))/(10000) = 7.8539* 10^(5)\ ly^(2)](https://img.qammunity.org/2020/formulas/physics/high-school/szv7kw6ylnqhaunixu7u7e52ypwwtzm7ch.png)
The radius of each area of civilization, r:
![A' = \pi r^(2)](https://img.qammunity.org/2020/formulas/physics/high-school/r5re0zhexm36pq9t7evs26heu8ofzcrbtz.png)
![r = \sqrt{(A')/(\pi)}](https://img.qammunity.org/2020/formulas/physics/high-school/e4dc0izrciy162vctifkaipdst3xzhrv9r.png)
![r = \sqrt{(7.8539* 10^(5))/(\pi)} = 499.968\ ly](https://img.qammunity.org/2020/formulas/physics/high-school/97g42o58n29j32o7hj8ud5w3cfmgywbg10.png)
Thus the average separation distance between civilizations is given as:
2r =
![2* 499.968 = 999.936\ ly](https://img.qammunity.org/2020/formulas/physics/high-school/s68ld9xqps5okqoud8smnv1k20azbg1z9s.png)