Question

Determine the volume (in ml) of a 3.57 M solution of Zi Bry that contains 0.884 moles of ZnBr2

Answer 1

The volume (in ml) of a 3.57 M solution of
`ZnBr_2` that contains 0.884 moles of
`ZnBr_2` is 247.61g mL

Step-by-step explanation:

According to the definition of Molarity

which sates

"The amount of moles of a substance present in one litre of the solution is called as Molarity."

3.57M
`ZnBr_2` solution implies that 1000 mL of the solution conatins 3.57Moles of
`ZnBr_2`

Hence , 3.57 moles of
`ZnBr_2` is present in the 1000 ml of solution

Now,

In 1 mole of
`ZnBr_2` is present in the =
`(1000)/(3.57)`ml of solution

Similarily ,

In 0.884 moles of
`ZnBr_2` is present in the
`(1000* 0.884)/(3.57)` of solution= 247.61g mL