Question

Consult Interactive Solution 10.37 to explore a model for solving this problem. A spring is compressed by 0.0647 m and is used to launch an object horizontally with a speed of 2.08 m/s. If the object were attached to the spring, at what angular frequency (in rad/s) would it oscillate?

Answer 1

`\omega=32.14\ rad/s`

Step-by-step explanation:

Given that,

The compression in the spring, x = 0.0647 m

Speed of the object, v = 2.08 m/s

To find,

Angular frequency of the object.

Solution,

We know that the elation between the amplitude and the angular frequency in SHM is given by :

`v=\omega* A`

A is the amplitude

In case of spring the compression in the spring is equal to its amplitude

`\omega=(v)/(A)`

`\omega=(2.08\ m/s)/(0.0647\ m)`

`\omega=32.14\ rad/s`

So, the angular frequency of the spring is 32.14 rad/s.