Question

The flavor of anise is due to anethole, a compound with the molecular forumal C10H12O. Combustion of one mole of anethole produces 5541 kJ of thermal energy. If 0.950 g of anethole is combusted in a bomb calorimeter whose heat capacity (Ccalorimeter) is 7.854 kJ/°C, what is the change in temperature of the calorimeter?

Answer 1

Change in temperature of calorimeter is
`4.52^(0)\textrm{C}`

Step-by-step explanation:

Molar mass of anethole = 148.2 g/mol

So, 0.950 g of anethole =
`(0.950)/(148.2)moles` of anethole = 0.00641 moles of anethole

1 mol of anethole releases 5541 kJ of heat upon combustion

So, 0.00641 moles of anethole release
`(5541* 0.00641)kJ` of heat or 35.52 kJ of heat

7.854 kJ of heat increases
`1^(0)\textrm{C}` temperature of calorimeter.

So, 35.52 kJ of heat increases
`((1)/(7.854)* 35.52)^(0)\textrm{C}` or
`4.52^(0)\textrm{C}` temperature of calorimeter

So, change in temperature of calorimeter is
`4.52^(0)\textrm{C}`