Question

A stone is thrown straight up from the edge of a roof, 775 feet above the ground, at a speed of 16 feet per second. A. Remembering that the acceleration due to gravity is −32ft/sec2, how high is the stone 4 seconds later?

Answer 1

The stone is approximately 583 feet high 4 seconds later.

Step-by-step explanation:

To find the height of the stone 4 seconds later, we can use the equation of motion for an object in free fall:

h = h0 + v0t + (1/2)gt^2

Where:

h = height at time t

h0 = initial height

v0 = initial velocity

g = acceleration due to gravity

t = time

Substituting the given values:

h = 775 + 16(4) + (1/2)(-32)(4)^2

h = 775 + 64 - 256

h = 583 feet

Therefore, the stone is approximately 583 feet high 4 seconds later.