Answer:
0.089557
Explanation:
Given thqt:
Mean, m = 45000
Standard = 10000
What percentage of trucks can be expected to travel either below 30 or above 65 thousand miles in a year
Below 30, 000
P(x < 30000)
Obtain the standardized score :
Z = (x - m) / s
Z = (30000 - 45000) / 10000
Z = - 15000 / 10000
Z = - 1.5
P(Z < - 1.5) = 0.066807
Above 65,000
P(x > 65000)
Obtain the standardized score :
Z = (x - m) / s
Z = (65000 - 45000) / 10000
Z = 20000 / 10000
Z = 2
P(Z > 2) = 0.02275 (Z probability calculator)
P(Z < - 1.5) + P(Z > 2)
0.066807 + 0.02275
= 0.089557