Answer:
v₂ = 3.44 m/s
Step-by-step explanation:
given,
Dan is gliding on skateboard at = 4 m/s
speed of skateboard = 8 m/s
mass of Dan = 50 Kg
mass of skateboard = 7 Kg
Speed of Dan when his feet hit the ground = ?
Using conservation of momentum
PE(initial) = PE(final)
(M+m)V = m v₁ + M v₂
(50+7)x 4 = 7 x 8 + 50 x v₂
50 x v₂ =172
v₂ = 3.44 m/s
speed of Dan when his feet hit the ground = v₂ = 3.44 m/s