Answer:
0.082
Explanation:
Number of attempts = n = 100
Since there are only two outcomes and in-dependent of each other, the probability of missing a shot = 1 - Probability of making each shot
p = 1 - 0.95 = 0.05
Possion Ratio (λ) = np where n is the number of events and p is the probability of the shot missing
λ = 100 x 0.05 = 5
Define X such that X = Number of misses and X ≅ Poisson (λ = 5)
P [X ≤ 2] = P [X = 0] + P [X = 1] + P [X = 2]
P [X ≤ 2] = e⁻⁵ + e⁻⁵ x 5 + e⁻⁵ x 5²/2!
P [X ≤ 2] = e⁻⁵ [1 + 5 + 5²/2!]
P [X ≤ 2] = e⁻⁵ x 12.25 = 0.082
The required probability that there are at most 2 misses in the first 100 attempts is 0.082