Question

The average intensity of light emerging from a polarizing sheet is 0.689 W/m2, and that of the horizontally polarized light incident on the sheet is 0.930 W/m2. Determine the angle that the transmission axis of the polarizing sheet makes with the horizontal.

Answer 1

`\theta=30.60^0`

Step-by-step explanation:

given,

intensity of light(S) = 0.689 W/m²

intensity of (S_0) = 0.930 W/m²

angle of transmission axis = ?

using Malus law

`s = s_0 cos^2\theta`

`cos^2\theta= (s)/(s_0)`

`cos\theta= \sqrt{(s)/(s_0)}`

`\theta=cos^(-1)(\sqrt{(s)/(s_0)})`

`\theta=cos^(-1)(\sqrt{(0.689)/(0.930)})`

`\theta=cos^(-1)(√(0.7408))`

`\theta=cos^(-1)({0.86073})`

`\theta=30.60^0`