Question

Solid aluminum hydroxide reacts with a solution of hydrobromic acid. Write a balanced molecular equation and a balanced net ionic equation

Answer 1

`Al(OH)_(3)(s)+3H^(+)(aq.)+3Br^(-)(aq.)\rightarrow Al^(3+)(aq.)+3Br^(-)(aq.)+3H_(2)O(l)`

`Al(OH)_(3)(s)+3H^(+)(aq.)\rightarrow Al^(3+)(aq.)+3H_(2)O(l)`

Step-by-step explanation:

Aluminium hydroxide (
`Al(OH)_(3)`) is a base and hydrobromic acid (HBr) is a strong acid.

Hence an acid-base reaction occurs between
`Al(OH)_(3)` and HBr

Balanced molecular equation:

`Al(OH)_(3)(s)+3HBr(aq.)\rightarrow AlBr_(3)(aq.)+3H_(2)O(l)`

Balanced total ionic equation:

`Al(OH)_(3)(s)+3H^(+)(aq.)+3Br^(-)(aq.)\rightarrow Al^(3+)(aq.)+3Br^(-)(aq.)+3H_(2)O(l)`

Balanced net ionic equation:

`Al(OH)_(3)(s)+3H^(+)(aq.)\rightarrow Al^(3+)(aq.)+3H_(2)O(l)`

(net ionic equation is written by removing common ions present in both side of total ionic equation)