Answer:
The power in this flow is
![9.56*10^(8)\ W](https://img.qammunity.org/2020/formulas/physics/college/2qbwyhzepocv05y0o62jgrm8syji4yfyjl.png)
Step-by-step explanation:
Given that,
Distance = 221 m
Power output = 680 MW
Height =150 m
Average flow rate = 650 m³/s
Suppose we need to calculate the power in this flow in watt
We need to calculate the pressure
Using formula of pressure
![Pressure=\rho g h](https://img.qammunity.org/2020/formulas/physics/college/sas3cxw3ka6xm514b00ep92hmotuz0t35v.png)
Where,
= density
h = height
g = acceleration due to gravity
Put the value into the formula
![Pressure=1000*9.8*150](https://img.qammunity.org/2020/formulas/physics/college/8omhn12694w74zyluluk1d9lwnaxen2p9u.png)
![Pressure=1470000\ Nm^2](https://img.qammunity.org/2020/formulas/physics/college/jeugof9boadq6hdx9zdxp3uflsgvdmf4zh.png)
We need to calculate the power
Using formula of power
![P=Pressure* flow\ rate](https://img.qammunity.org/2020/formulas/physics/college/enyq5jupewdn11ya1hwl8u17eer6tdtbny.png)
Put the value into the formula
![P=1470000*650](https://img.qammunity.org/2020/formulas/physics/college/91x2ycyfmzsr733vcjsx5oqaycw7yx75me.png)
![P=9.56*10^(8)\ W](https://img.qammunity.org/2020/formulas/physics/college/s531n4359swb205dhrvvnizyrk3us9s9s7.png)
Hence, The power in this flow is
![9.56*10^(8)\ W](https://img.qammunity.org/2020/formulas/physics/college/2qbwyhzepocv05y0o62jgrm8syji4yfyjl.png)