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What happens to the wavelength of a wave on a string when the frequency is doubled

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Answer:


\lambda'=(1)/(2)* \lambda

Step-by-step explanation:

The number of oscillation per unit time is called frequency of a wave while the distance between two consecutive crests and the trough is called its wavelength.

The wavelength of a wave is given by :


\lambda=(v)/(f)

If frequency is doubled, f' = 2f


\lambda'=(v)/(f')


\lambda'=(v)/(2f)


\lambda'=(1)/(2)* (v)/(f)


\lambda'=(1)/(2)* \lambda

So, when the frequency is doubled the wavelength of a wave on the string becomes half.

User Jitendra Modi
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