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A rectangular wire loop is pulled out of a region of uniform magnetic field B at a constant speed v. What is true about the induced emf in the loop while the loop is pulled out of the region of uniform magnetic field

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Answer:

There is a constant emf induced in the loop.

Step-by-step explanation:

In the uniform magnetic field suppose the rectangular wire loop of length L and width b is moved out with a uniform velocity v. suppose any instance x length of the loop is out of the magnetic field and L-x length is inside the loop.

Area of loop outside the field = b(L-x)

we know that flux φ= BA

B= magnitude of magnetic field , A= area

and emf
\epsilon= (d\phi)/(dt)


\epsilon=B(dA)/(dt)


\epsilon=B(db(L-x))/(dt)


\epsilon=Bb(d(L-x))/(dt)

B,b and L are constant and dx/dt = v

⇒ε = -Bbv

which is a constant hence There is a constant emf induced in the loop.

User Hester Lyons
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