Question

A gold ring was purchased from a street vendor for a ridiculously low price. the buyer has brought the ring to you to conform its metal content. you have found the mass of the ring to be 23.46 h and its volume to be 2.25 cm3. what do you tell the buyer?

Answer 1

Step-by-step explanation:

`\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}`

We are given:

Mass of liquid = 23.46 g

Volume occupied by the ring =
`2.25 cm^3`

Density of gold ring = D

`D=(23.46 g)/(2.25 cm^3)=10.43 g/cm^3`

Original density of gold =
`19.3 g/cm^3`

`10.43 g/cm^3<19.3 g/cm^3`

We will tell the buyer that gold ring purchased from him is too adulterated with other metals which have reduced its density indication that it is an artificial gold ring.