Question

A line intersects the points (-22, -14) and

(-18, -12). What is the slope-intercept
equation for this line?
y = 4x+

Answer 1

`y=(1)/(2)x-3`

Explanation:

we know that

The equation of the line in slope intercept form is

`y=mx+b`

where

m is the slope or unit rate

b is the y-intercept or initial value

step 1

Find the slope

we have the points

(-22, -14) and (-18, -12)

The formula to calculate the slope between two points is equal to

`m=(y2-y1)/(x2-x1)`

substitute the values in the formula

`m=(-12+14)/(-18+22)`

`m=(2)/(4)`

simplify

`m=(1)/(2)`

step 2

Find the y-intercept b

we have

`m=(1)/(2)`

`point\ (-22,-14)`

substitute

`y=mx+b`

`-14=(1)/(2)(-22)+b`

solve for b

`-14=-11+b`

`b=-14+11`

`b=-3`

substitute

`y=(1)/(2)x-3`