206k views
3 votes
If the radius of a blood vessel drops to 84.0% of its original radius because of the buildup of plaque, and the body responds by increasing the pressure difference across the blood vessel by 10.0%, what will have happened to the flow rate? The flow rate will have changed to ...... % of its original value.

User RickJames
by
5.6k points

1 Answer

6 votes

To develop this problem it is necessary to apply the equations concerning Bernoulli's law of conservation of flow.

From Bernoulli it is possible to express the change in pressure as


\Delta P = (1)/(2)\rho (v_1^2-v_2^2)+ \rho g (h_1h_2)

Where,


v_i =Velocity


\rho = Density

g = Gravitational acceleration

h = Height

From the given values the change of flow is given as


R = r^4P

Therefore between the two states we have to


(R_2)/(R_1) = (r_2^4 P_2)/(r_1^4 P_1) *100\%


(R_2)/(R_1) = (84^4 (110))/(100^4*(100)) *100\%


(R_2)/(R_1) = 54.77\%

The flow rate will have changed to 54.77 % of its original value.

User Sindrenm
by
5.8k points