Question

An air gun fires 2 gram pellets at 60 m/s at a 45 gram golfball initially at rest. The pellets rebound at a speed 40 m/s and are fired at a rate of 4 per second, How much momentum is delivered to the golf ball each second in kg*m/s

Answer 1

0.16 kgm/s

Step-by-step explanation:

`m_1` = Mass of pellet = 2 g

`m_2` = Mass of golf ball = 45 g

`u_1` = Initial Velocity of pellet = 60 m/s

`u_2` = Initial Velocity of golf ball = 0 m/s

`v_1` = Final Velocity of pellet = 40 m/s

`v_2` = Final Velocity of golf ball

In this system the linear momentum is conserved

`m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow m_2v_2=m_1u_1+m_2u_2-m_1v_1\\\Rightarrow m_2v_2=0.002* 60+0-0.002* 40\\\Rightarrow m_2v_2=0.04`

As the golf ball is being shot 4 times every second the momentum delivered to the golf ball each second is
`4* 0.04=0.16\ kgm/s`