Question

The mass of a compound is taken 5 times with the following results: 26.6 mg, 26.3 mg, 26.2 mg, 26.4 mg, and 26.1 mg. If

the true mass is 25.6 mg, what is the percent relative error for this set of data? Round to the nearest hundredth of a
percent.

Answer 1

2.813%

Step-by-step explanation:

First, we must take the average of the five mass measurements

Average value= sum of all five trials/ 5= 26.6 + 26.3 + 26.2 + 26.4 +26.1 /3 = 26.32mg

Now, we have been provided the accurate mass of the compound in the question as 25.6mg

Remember that relative percent error = Average value of measurement - True value of measurement / true value×100

Hence we have;

Percent error=

26.32 - 25.6/25.6 ×100

Percent error= 2.813%