Step-by-step explanation:
Given that,
Average force exerting on the golf club, F = 1000 N
Mass of the ball, m = 0.045 kg
Initial speed of the ball, u = 0
The time of contact between the ball and the club,

1. Let v is the speed of the golf ball as it leaves the tee. The product of force and time is equal to the change in its momentum as :




v = 40 m/s
2. Force applied by the batter, F = 8000 N
Time,

Let J is the magnitude of the impulse delivered to the baseball. It is equal to the product of force and time as :


J = 8.8 kg-m/s