Answer:
Option D.
Explanation:
In the figure attached, Diagonals AC and BD are bisecting each other at a point P.
That means AP ≅ CP and DP ≅ BP
We have to prove : AB ≅ DC and AB ║ DC
Proof : In triangles BPA and CPD,
AP ≅ CP
DP ≅ BP
∠ APB ≅ ∠DPC [vertically opposite angles]
Therefore, by postulate SAS [Side-Angle-Side]
ΔBCP ≅ ΔCDP
Option D. will be the answer.