Answer:
Explanation:
let the consecutive even numbers be 2n-2,2n,2n+2,2n+4 where n>0 and n is an integer.
2n(2n+2)-(2n-2)(2n+4)
=4n²+4n-(4n²+8n-4n-8)
=4n²+4n-4n²-8n+4n+8
=8
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