Answer: Specific heat of the metal is

Step-by-step explanation:

As we know that,

.................(1)
where,
q = heat absorbed or released
= mass of metal = 40.0 g
= mass of water = 65.0 g
= final temperature =

= temperature of metal =

= temperature of water =

= specific heat of metal = ?
= specific heat of water=

Now put all the given values in equation (1), we get
![40.0* c_1* (366.27-298)=-[65.0* 4.184* (366.27-373)]](https://img.qammunity.org/2020/formulas/chemistry/high-school/agoip216ll2kh3o99klj6vqairrtlc5lom.png)

Therefore, the specific heat of the metal is
