Question

A roller coaster speeds up with constant acceleration for 2.3 s until it reaches a velocity of 35 m/s. During this time, the roller coaster travels 41m. What is the initial velocity of the roller coaster before it begins to accelerate?

Answer 1

x=(v+v0)/2 t

Step-by-step explanation:

Answer 2

0.65 m/s

Step-by-step explanation:

Applying the equation,

v = u + at

35 = u + a×2.3 -(1)

Again, applying the equation,

s = ut +
`(1)/(2)`a
`t^(2)`

41 = u×2.3 +
`(1)/(2)` ×
`(2.3)^(2)`

35.65 = 2u + 2.3a -(2)

comparing first and second we get u= 0.65 m/s