Question

To sterilize a 53.0 g glass baby bottle, we must raise its temperature from 25.0°C to 92.0°C. How much heat transfer (in J) is required?

Answer 1

The heat transferred is, Q = 2982.84 J

Step-by-step explanation:

Given data,

The mass of the glass bottle, m = 53 g

= 0.053 kg

The change on temperature, ΔT = T² - T₁

= 92 - 25

= 67 ° C

The formula for heat transfer is,

Q = mcΔT

Where,

c - specific heat capacity of the material

Substituting the values

Q = 0.053 x 840 x 67

= 2982.84 J

Hence, the heat transferred is, Q = 2982.84 J