Question

Please help im finding this very difficult

Answer 1

First calculate price per gram (J) of both jars.

Large jar:
`J_L=\frac{440\mathrm{g}}{1.54\mathrm{£}}\approx 285.71 \mathrm{(g)/(£)}`

Small jar:
`J_S=\frac{340\mathrm{g}}{1.26\mathrm{£}}\approx 269.84\mathrm{(g)/(£)}`

Because
`J_S < J_L` we can conclude
`J_S` has best value.

Hope this helps.