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A tennis ball is released from a height of 4.0 m above the floor. After its third bounce off the floor, it reaches a height of 183 cm. What percentage of its mechanical energy does it lose with each bounce?

23%

27%

20%

15%

User Ineu
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6.1k points

2 Answers

6 votes

Answer: 23

Explanation: gradpoint

User Performanceuser
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6.3k points
6 votes

Answer:

The percentage of its mechanical energy does the ball lose with each bounce is 23 %

Step-by-step explanation:

Given data,

The tennis ball is released from the height, h = 4 m

After the third bounce it reaches height, h' = 183 cm

= 1.83 m

The total mechanical energy of the ball is equal to its maximum P.E

E = mgh

= 4 mg

At height h', the P.E becomes

E' = mgh'

= 1.83 mg

The percentage of change in energy the ball retains to its original energy,


\Delta E\%=(1.83mg)/(4mg)*100\%

ΔE % = 45 %

The ball retains only the 45% of its original energy after 3 bounces.

Therefore, the energy retains in each bounce is

∛ (0.45) = 0.77

The ball retains only the 77% of its original energy.

The energy lost to the floor is,

E = 100 - 77

= 23 %

Hence, the percentage of its mechanical energy does the ball lose with each bounce is 23 %

User Shadocko
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