Question

Write an equation for a line that passes through (5,-3) and (-10,15)

Answer 1

y+3=-6/5(x-5)

Explanation:

Let’s write it in point-slope form which is (y-y1) = m(x-x1)

Slope=m=(change in y)/(change in x) = (-3-15)/(5-(-10))=-18/15=-6/5

Now let’s insert a point. Either point will work but I’ll choose (5,-3). So let’s substitute:

(y-y1) = m(x-x1)

y+3=-6/5(x-5)

Other ways would’ve worked. This is the way that works best for me. So, I hope this helped!

Answer 2

y = -6/5x+3

Explanation:

To find the equation, first find the slope of the line. For any two points (x1, y1) and (x2, y2), the slope is given by the following.

Now, use one of the given points, the slope, and the point-slope form of an equation of a line.