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in a football league , 3 points are given for a win. 1 for draw and 0 for loss. After praying 30 games, a team lost 9 games and gained 47. How many games did it wins?

User Davidgh
by
5.1k points

1 Answer

4 votes

Answer:

15 wins and 6 draws

Explanation:

Here I will use indifferently the words tie and draw.

If the team played 30 and lost 9 it must have won or tied 21 games. Lets call w a win and t a tie we have that:

w + t = 21 [equation 1]

The 47 points it gained are due to either victories, that give 3 p, or ties, that give 1 p. So, the total 47 points can be expressed as:

3w + t = 47 [equation 2]

Take now equation 1 and get the value of w in function of t (or t in function of w):

w = 21 - t

Now replace it in equation t:

3(21-t) + t = 47

63 - 3t + t = 47

63 -2t = 47

subtract 63 in both sides:

-2t = -16

t = -16/-2

t = 8

So, the team draws 8 games. Lets replace it in equation 1 to get w:

w + 6 = 21

Subtract 6 in both sides:

w = 15

And the team won 15 games.

Solutions: 15 wins and 6 draws

User LonelySoul
by
5.9k points
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