Question

A 340 g bird flying along at 6.0 m/s sees a 13 g insect heading straight toward it with a speed of 30 m/s. The bird opens its mouth wide and enjoys a nice lunch. What is the bird's speed immediately after swallowing?

_____m/s

Answer 1

V = 4.67 m/s

Step-by-step explanation:

given,

mass of the flying bird (M)= 340 g = 0.34 Kg

Speed of bird(u₁) = 6 m/s

mass of insect(m) = 13 g = 0.013 Kg

speed of insect(u₂) = 30 m/s

Speed of bird after eating the insect(V) =?

Using conservation of momentum

M u₁ + m u₂ = (M+m)V

`V = (M u_1+ m u_2)/((M+m))`

`V = (0.34* 6 - 0.013 * 30)/(0.34+0.013)`

`V = (1.65)/(0.353)`

V = 4.67 m/s

the bird's speed immediately after swallowing V = 4.67 m/s