Question

1. A 0.250 kg baseball sits on the ledge of a window in Treadwell hall. If the ball has 18.5

Joules of potential energy, how high is the ball?
2. How long would it take to hit the ground?​

Answer 1

h = 7.54 m

t = 1.24 s

Step-by-step explanation:

1.Let g = 9.81 m/s2 is the gravitational acceleration. Since the formula for potential energy is:

`E_p = mgh`

where m = 0.25 is the ball mass and h is the height. We can solve for h

`h = (E_p)/(mg) = (18.5)/(0.25*9.81) = 7.54m`

2. The time it take for the ball to reach a distance of 7.54m with a gravitational acceleration of 9.81m/s2:

`h = (gt^2)/(2)`

`t^2 = (2h)/(g) = (2*7.54)/(9.81) = 1.54`

`t = √(1.54) = 1.24 s`