Question

The diameters of the main rotor and tail rotor of a single-engine helicopter are 7.56 m and 1.00 m, respectively. The respective rotational speeds are 453 rev/min and 4137 rev/min. Calculate the speeds of the tips of both rotors.

Answer 1

Step-by-step explanation:

Given

Diameter of main rotor
`d_1=7.56 m`

Tail rotor
`d_2=1 m`

`N_1=453 rev/min`

`N_2=4137 rev/min`

`\omega =(2\pi N)/(60)`

`\omega _1=(2\pi 453)/(60)=47.44 rad/s`

`\omega _2=(2\pi 4137)/(60)=433.28 rad/s`

Speed of the tip of main rotor
`=\omega _1* r_1=47.44* (7.56)/(2)=179.32 m/s`

Speed of tail rotor
`=\omega _2* r_2=433.28* (1)/(2)=216.64 m/s`